Matching LM-2 with HP Tuners.
First you need to have wired the LM-2 output 1 with de HP Tuner Input, the correct way.
The Output of the LM-2 is linear from 0-5 Volts regarding how it is program will display and AFR value to a corresponding voltage.
Knowing this the equation is de following Y = M * X + B , to have correct relation we need to know 2 points to get the correct values.
In hp tuner log the raw voltage from de input or define one by yourself setting the direct input formula like this y = Volts / 1 + 0 .
Start your vehicle and wait until the afr is stable at 14.7 probably you need rev up a little bit the engine.
When the LM2 AFR is 14.7, record the voltage at HP Tuners. For Example, lets say we read 2.45 volts,
then we have our first point: AFR = 14.7 Volts = 2.45
Now the easy way to get our second point is to make a copy of your VCM program, and modify it to work in open loop, and in the Open Loop EQ Ratio table set it to 1.30 every cell above 40° ECT, with this, you are forcing to have a rich AFR, write the calibration, start the engine and start logging, wait until the afr is stable, (may need a little rev ups), and record the afr value, let say it is: AFR 11.3 and the volts of hp tuners log is 0.80 volts, Stop your engine, and write your original calibration file to return to normal.
Our second points is: AFR 11.3 Volts 0.80
With the 2 known points, we can make the proper calculation for our equation.
M = (Y2 – Y1) / (X2 –X1) so M = (14.7 – 11.3) / (2.45 – 0.80) is 2.0606
B = Y – M * X so B = 14.7 – (2.0606 * 2.45) is 9.6515
For the HP tuners the M has to be a divisor not a multiplier so
1/ M = 1 / 2.0606 is 0.4852
Now in the hp tuners make a user defined called WB-LM-2 and put this formula
Y = Volts / 0.485 + 9.65
And you are ready.