If the dyno has a stoich of 14.67 and I have a stoich of 14.19 for E10 is the 12.85 AFR really about a 12.4 AFR?
14.19/14.67 x 12.85 is around 12.4
Or is afr just that?
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If the dyno has a stoich of 14.67 and I have a stoich of 14.19 for E10 is the 12.85 AFR really about a 12.4 AFR?
14.19/14.67 x 12.85 is around 12.4
Or is afr just that?
Hopefully I don't confuse myself here but stoich is stoich and for your case it's E10/14.13ish or so. So then you'd just still commanded whatever AFR you want to run based off the stoich/fuel you are using.
Are you saying the dyno place runs E0 fuel??
have to think in terms of lambda. AFR is a conversion.
if stoich in the tank is 14.2 and stoich on the dyno is 14.7 then both = lambda 1.0
target the lambda for whats in the tank and multiply it by the dyno stoich afr and you will have your dyno afr target.
or just set everything up for lambda and stop converting.
So this has already happened where the stoich on the dyno was 14.67 and my stoich was 14.13.
The p.e. was set to 1.17. That gives a lambda of a little over .85
14.67/1.17 is 12.53
The dyno read 12.85.
12.53/12.85 is around .975
It seems to me that I should enrichen the maf calibration by 2.5% upwards to attain the 12.53 on the dyno. (theoretically)
And then we would get 14.13/1.17 = 12.07 on E10. (what I have in my tank and it has been tested)
Is that correct or did I make it too complicated. I cannot get back on the dyno for a while.
If the dyno thinks stoich is 14.67, and it's reading 12.85, then it's reading Lambda 0.876.
If you're commanding PE to 1.17, then that's Lambda 0.855.
100*(actual - commanded)/commanded = % error.
100*(0.876-0.855)/0.855=2.46% error.
This means you're 2.46% lean.